Physics Electrostatics Potential & Capacitance Properties of Charge and Coulomb's Law MCQ (Single Correct)

Two equal negative charges –q each are fixed at the points (0, a) and (0, -a) on the y-axis. A positive charge Q is released from rest at the point (2a, 0) on the x-axis. The charge Q will:

A
Execute simple harmonic motion about the origin
B
At origin velocity of particle is maximum.
C
Move to infinity
D
Execute oscillatory but not simple harmonic motion.

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
CHECK THE SOLUTION.

(b, d)

(i) From diagram, force on Q at general position x, is given by

F net = – 2F cosθ = – (Towards origin)

(ii) When charge moves from (2a, 0) to origin O, force keeps on acting on Q and becomes zero at O.

∴ Velocity of Q is max. at O.

(iii) Motion is SHM for very small displacements. & 2a is not very small os motion is periodic but not SHM.

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.